Supportin (dot)

Jan 4, 2013 at 2:32 PM

I have a binary expression that I am parsing and it works great until I put a dot.

This works:
x = 3 AND (y = 4)

This does not work:
x.Value = 3 AND (y = 4)

Error I Get:
Invalid Character "."

Any thoughts?  There is nothing specific in my grammar discussing anything at all with the character ".".  i.e. I want it to be treated just like a normal string character would. 

Jan 4, 2013 at 9:28 PM

add "." to the list of allowed characters in IdentifierTerminal constructor